The bearings of P and Q from a common point N are 020° and 300° respectively. If P and Q are also equidistant from N, find the bearing of P from Q.
From the diagram above, <PNQ = 80º
But < PQN = <NPQ = 50º ( base <s of isosceles triangle PQN)
Therefore, the bearing of P from Q = 070º
There is an explanation video available below.
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