If 2\(_9\) x (Y3)\(_9\) = 3\(_5\) x (Y3)\(_5\), find the value of Y.
(2 x 9 \(^0\) ) (Y x 9 \(^1\)+ 3 x 9\(^0\)) = (3 x 5 \(^0\))(Y x 5\(^1\) + 3 x 5\(^0\)). (2 * 1)(Y *9 + 3) = (3 * 1)(Y * 5 + 3) 18y + 6 = 15y + 9
18y - 15y = 9 - 6
3y = 3
y = 1
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