A straight line makes an angle of 30° with the positive x-axis and cuts the y-axis at y = 5. Find the equation of the straight line.
Cos 30 = \(\frac{5}{\text{x}}\)
x cos 30 = 5, => x = 5\(\sqrt{3}\)
Coordinates of P = - 5\(\sqrt{3}\), 0
Coordinates of Q = 0, 5
Gradient of PQ = (y\(_2\) - y\(_1\)) (X\(_2\) - X\(_1\)) = \(\frac{(5 - 0)}{(0 - 5\sqrt{3}}\))
= \(\frac{5}{5\sqrt{3}}\) = \(\frac{1}{\sqrt{3}}\)
Equation of PQ = y - y\(_1\) = m (x -x\(_1\))
y - 0 = \(\frac{1}{\sqrt{3}}\) (x -( -5\(\sqrt{3}\)))
Thus: \(\sqrt{3}\)y = x + 5\(\sqrt{3}\)
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