What is the answer when 2434\(_6\) is divided by 42\(_6\)?
236
356
526
556
Explanation
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R2434 base 6 is divided by 42 base 6?
Solution
Let 2434 base 6=Y & 42 base 6=Z
Y=(2 x 6^3) + (4 x 6^2) + (3 x 6^1) + (4 x 6^0)
Y=(2 x 216) + (4 x 36) + (3 x 6) + (4 x 1)
Y=432 + 144 + 18 +4
Y=598
Z= 42 base 6
Z=(4 x 6^1) + (2 x 6^0)
Z=(4 x 6) + (2 x 1)
Z=24 + 2
Z=26
.: Y/Z
=598/26
=23 base 6
.: 2432 base 6 divide by 42 base 6 is 23 base 6
6 | 23
6 | 3r5
| 0r3
so u countin 4rm down and dats 35

2x6^3+4x6^2+3x6^1+4x6^0
=2x216+4x36+18+4.
=432+144+18+4
=598.
=>42base6. 4x6+2x0=26. 598/26=23.
=>23/6=35base6

2434 base 6 is divided by 42 base 6?
Solution
Let 2434 base 6=Y & 42 base 6=Z
Y=(2 x 6^3) + (4 x 6^2) + (3 x 6^1) + (4 x 6^0)
Y=(2 x 216) + (4 x 36) + (3 x 6) + (4 x 1)
Y=432 + 144 + 18 +4
Y=598
Z= 42 base 6
Z=(4 x 6^1) + (2 x 6^0)
Z=(4 x 6) + (2 x 1)
Z=24 + 2
Z=26
.: Y/Z
=598/26
=23 base 6
.: 2432 base 6 divide by 42 base 6 is 23 base 6

(Hint) -> CONVERTING TO BASE10
1st step- pick each of the numbers given by multiplying it by the given.
2nd step- start from the last on your right by giving the ^power starting from (0 1 2 3......till it get to the left end where you find none to be given.
[here]->
2434base6 = (2*6)^3 + (4*6)^2 + (3*6)^1 + (4*6)^0
= (2*216) + (4*36) + (3*6) + (4*1)
= 432 + 144 + 18 + 4
= 598base6
42base6 = (4*6)^1 + (2*6)^0
= (4*6) + (2*1)
= 24 + 2
=26base6
now 2434base6 = 598 & 42base6 = 26. divide ( 598/26 = 23base6 )
NOTE: you were solving in base 10 not 6,you need to convert back to base 6.
[here]-> 23base6 = 23/6 (not just a division)
(use tabular form)
- 6 in 23 = 3 Remainder 5
- 6 in 3 is impossible then put down the 3
then point your arrow up from 3 to 5 upwards.
that's -> 35 (ans)

look I will continue from ifechuks solving after u have divide 598/26=23 to arrive at the perfect and u convert to from base ten to six like 23/6=3r5 while3/6=0r3 u are expected to pic only remender from below link r3 and r5 making 35 base 6

in converting your answer back to base 6, why do you use 6 in dividing when there are small numbers that can divide it and why dividing using six,how do you get 6 into 3 and it will give you 0 R 3 ,can I get an explanation

in converting your answer back to base 6, why do you use 6 in dividing when there are small numbers that can divide it and why dividing using six,how do you get 6 into 3 and it will give you 0 R 3 ,can I get an explanation??

R2434 base 6 is divided by 42 base 6?
Solution
Let 2434 base 6=Y & 42 base 6=Z
Y=(2 x 6^3) + (4 x 6^2) + (3 x 6^1) + (4 x 6^0)
Y=(2 x 216) + (4 x 36) + (3 x 6) + (4 x 1)
Y=432 + 144 + 18 +4
Y=598
Z= 42 base 6
Z=(4 x 6^1) + (2 x 6^0)
Z=(4 x 6) + (2 x 1)
Z=24 + 2
Z=26
.: Y/Z
=598/26
=23 base 6
.: 2432 base 6 divide by 42 base 6 is 23 base 6




