### If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?

If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?
• A. (5/2)
• B. -(5/4)
• C. -(25/4)
• D. -10
##### Explanation
Hint: apply basic mathematics rules beginning from BODMAS to algebra, and follow solution carefully to arrive at p =(5/2), q = -(25/4) and r = -(9/2).

Then p+2q will give you $$\frac{5}{2}+2\left(\frac{-25}{4}\right)= -10$$

#### Contributions (62)

Both d questn nd d answer is nt clear 2 me.
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• suntoozee: that means u are honest
1 year ago
this is cool am lovin this.... OMG i love this site u guys are the best... Wow! Nothing compares to this... Keep the good work up.. I'll go tell my friends,,,, u just got ur selves lots of members from my department....
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using the laws of indices u get the values of p=5/2, q=-25/4 and r=-17/4 then you solve p +2q which gives -10
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• Jesus is Lord: You are absolutely correct! you go school well well.
4 years ago
• alaleyo damilola: i dnt understand it very wel
3 years ago
dnt even undastand d qstion
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Soln

[a^2(3/4)b^-3(3/4)c^(3/4)]divided by (a^-1b^4c^5)

===>(a^3/2b^-9/4c^3/4)divided by (a^-1b^4c^5).

Note a^p =3/2-(-1)==>p=5/2

q=-9/4-(4)===>q=-25/4

r=3/4-(5)===>r=-17/4

now p+2q

5/2+2(-25/4)

:- p+2q=-10.

Make use of indice...
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• lamboy001: guy,i dey feel u,i undastand it nw
6 years ago
• TAIWO KHADIJAT: pls guyz explain to me
2 years ago
• psamson.sh8: Thanks for your explanation. God bless you
2 years ago
• Hannat001: Is it waec question?
1 month ago
Soln

[a^2(3/4)b^-3(3/4)c^(3/4)]divided by (a^-1b^4c^5)

===>(a^3/2b^-9/4c^3/4)divided by (a^-1b^4c^5).

Note a^p =3/2-(-1)==>p=5/2

q=-9/4-(4)===>q=-25/4

r=3/4-(5)===>r=-17/4

now p+2q

5/2+2(-25/4)

:- p+2q=-10.

Make use of indice...
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• okunola nifemi: nyc guy Waldon weldone.
5 years ago
• hibramed: U are a guru
4 years ago
• suntoozee: amsu
1 year ago
9 months ago
Is this what we want to solve in UTME......yea!I don suffer :(
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• sammy6829: u re nt serious, u have to be a man.
5 years ago
• lily.u.: each time I see past UTME maths ?s my hrt always beat twice faster than normal.
4 years ago
Haha read hard n pray papa God day
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• blitzjosh: Make u na help me understand dis tin
3 years ago
a^6/4b^-9/4c^3/4 for d numerator wen u multiply 3/4 For d denominator q^-1b^4c^5

Apply the law of indices u will gt a^10/4b^-25/4c^-17/4(In a^p b^q c^r)

but the questn is d value of p+2q i.e p=10/4 q=-25/4 Substitute it in p+2q so 10/4+2(-25/4)=10/4-50/4 =40/4=-10
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y is mathematics so simple for some pple,mehn i need thorough brushing up
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This question is really great.what you need to first is to open the bracket then use indices to remove the division sign to subtraction sign then after which you compare to get p,q and r.then u can substitute it into p+2q.that's it.you just need to tink hard.
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• Bukatti: i followed what you said but i approximated it to get -10 am i right
9 months ago
This question is really great.what you need to do first is to open the bracket then use indices to remove the division sign to subtraction sign then after which you compare to get p,q and r.then u can substitute it into p+2q.that's it.you just need to tink hard.
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after breaking it with the law indices u will get a^5/2 b^-25/4 c^-17/4 note: that the question ask for this p+2q=? knowing that a^p b^q c^r than fix in the value when p=5/2 and q=-25/4.in solving 5/2+2(-25/4)=-10 as the answer.
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Lord help me in mathematic soln
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This seems hard but using the laws of indices, it'll look so freaking easy, that triumphant feelin you get when you solve something right :D
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