### If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?

If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?
• A. (5/2)
• B. -(5/4)
• C. -(25/4)
• D. -10
##### Explanation
Hint: apply basic mathematics rules beginning from BODMAS to algebra, and follow solution carefully to arrive at p =(5/2), q = -(25/4) and r = -(9/2).

Then p+2q will give you $$\frac{5}{2}+2\left(\frac{-25}{4}\right)= -10$$

#### Contributions (61)

lucybaby2008
6 years ago
Both d questn nd d answer is nt clear 2 me.
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• suntoozee: that means u are honest
7 months ago
6 years ago
this is cool am lovin this.... OMG i love this site u guys are the best... Wow! Nothing compares to this... Keep the good work up.. I'll go tell my friends,,,, u just got ur selves lots of members from my department....
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Dagijoe
6 years ago
using the laws of indices u get the values of p=5/2, q=-25/4 and r=-17/4 then you solve p +2q which gives -10
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• Jesus is Lord: You are absolutely correct! you go school well well.
4 years ago
• alaleyo damilola: i dnt understand it very wel
3 years ago
rachel b michael
6 years ago
dnt even undastand d qstion
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Waldon95
6 years ago
Soln

[a^2(3/4)b^-3(3/4)c^(3/4)]divided by (a^-1b^4c^5)

===>(a^3/2b^-9/4c^3/4)divided by (a^-1b^4c^5).

Note a^p =3/2-(-1)==>p=5/2

q=-9/4-(4)===>q=-25/4

r=3/4-(5)===>r=-17/4

now p+2q

5/2+2(-25/4)

:- p+2q=-10.

Make use of indice...
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• lamboy001: guy,i dey feel u,i undastand it nw
5 years ago
• TAIWO KHADIJAT: pls guyz explain to me
2 years ago
• psamson.sh8: Thanks for your explanation. God bless you
2 years ago
Waldon95
6 years ago
Soln

[a^2(3/4)b^-3(3/4)c^(3/4)]divided by (a^-1b^4c^5)

===>(a^3/2b^-9/4c^3/4)divided by (a^-1b^4c^5).

Note a^p =3/2-(-1)==>p=5/2

q=-9/4-(4)===>q=-25/4

r=3/4-(5)===>r=-17/4

now p+2q

5/2+2(-25/4)

:- p+2q=-10.

Make use of indice...
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• okunola nifemi: nyc guy Waldon weldone.
4 years ago
• hibramed: U are a guru
3 years ago
• suntoozee: amsu
7 months ago
3 months ago
Omotayo isaac
6 years ago
Is this what we want to solve in UTME......yea!I don suffer :(
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• sammy6829: u re nt serious, u have to be a man.
4 years ago
• lily.u.: each time I see past UTME maths ?s my hrt always beat twice faster than normal.
4 years ago
Ali Inuwa Tanko
6 years ago
Haha read hard n pray papa God day
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• blitzjosh: Make u na help me understand dis tin
3 years ago
kingdomvic
6 years ago
a^6/4b^-9/4c^3/4 for d numerator wen u multiply 3/4 For d denominator q^-1b^4c^5

Apply the law of indices u will gt a^10/4b^-25/4c^-17/4(In a^p b^q c^r)

but the questn is d value of p+2q i.e p=10/4 q=-25/4 Substitute it in p+2q so 10/4+2(-25/4)=10/4-50/4 =40/4=-10
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Nabo Green
6 years ago
y is mathematics so simple for some pple,mehn i need thorough brushing up
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maxi957
6 years ago
This question is really great.what you need to first is to open the bracket then use indices to remove the division sign to subtraction sign then after which you compare to get p,q and r.then u can substitute it into p+2q.that's it.you just need to tink hard.
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• Bukatti: i followed what you said but i approximated it to get -10 am i right
3 months ago
maxi957
6 years ago
This question is really great.what you need to do first is to open the bracket then use indices to remove the division sign to subtraction sign then after which you compare to get p,q and r.then u can substitute it into p+2q.that's it.you just need to tink hard.
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VITALISIBEKWE
6 years ago
after breaking it with the law indices u will get a^5/2 b^-25/4 c^-17/4 note: that the question ask for this p+2q=? knowing that a^p b^q c^r than fix in the value when p=5/2 and q=-25/4.in solving 5/2+2(-25/4)=-10 as the answer.
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Saraphy
5 years ago
Lord help me in mathematic soln
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emili
5 years ago
This seems hard but using the laws of indices, it'll look so freaking easy, that triumphant feelin you get when you solve something right :D
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