If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?

If $$\frac{(a^2 b^{-3}c)^{\frac{3}{4}}}{a^{-1}b^{4}c^{5}}=a^{p} b^{q} c^{r}$$ What is the value of p+2q?
• A. (5/2)
• B. -(5/4)
• C. -(25/4)
• D. -10
Explanation
Hint: apply basic mathematics rules beginning from BODMAS to algebra, and follow solution carefully to arrive at p =(5/2), q = -(25/4) and r = -(9/2).

Then p+2q will give you $$\frac{5}{2}+2\left(\frac{-25}{4}\right)= -10$$

Contributions (61)

at least this one has been solved, for me i'd just say use the indicies law, calculate in d power for all of them i.e a,b and c then equate the answers to the unknown variables of the respective base i.e p,q and r after you have done that, solve like normal plus and minus, your ansa will appear
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Both d questn nd d answer is nt clear 2 me.
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• suntoozee: that means u are honest
7 months ago
na wa day say we should come and be completing with this artificial intelligence( computer) which is suppose to be done by an artificial work done ( dat is robot ) u cant win onless u too are robot,
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Lord help me in mathematic soln
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Which kin question b dis. Wats d meanin of \, /, {, }, confusion occupying my brain.
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yeah waldon get sense
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gud one
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y is mathematics so simple for some pple,mehn i need thorough brushing up
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I tink the question is not correct
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I dnt understand it oh please help me out   Follow
Smbody xplain how cum we r getn 3/4 -5=17/4 instead of 23/4...whr waz 3 removd?
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Haha read hard n pray papa God day
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• blitzjosh: Make u na help me understand dis tin
3 years ago
From laws of indices a^x/a^y=x-y..

a^p=3/2-(-1/1)=3+2/2 =5/2

p=5/2

b^q=-9/4-4/1=-9-16/4 =-25/4

q=-25/4

c^r=3/4-5/1=3-20/4=-17/4

r=-17/4

p+2q=5/2+2(25/4)

=5/2+50/4

=-40/4

=-10

p+2q=-10
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