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If two graphs y = px\(^2\) + q and y = 2x\(^2\) -1 intersect at...

Mathematics
JAMB 2001

If two graphs y = px\(^2\) + q and y = 2x\(^2\) -1 intersect at x = 2, find the value of p in terms q.

  • A. \(\frac{q-8}{7}\)
  • B. \(\frac{7-q}{4}\)
  • C. \(\frac{8-q}{2}\)
  • D. \(\frac{7+q}{8}\)
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Correct Answer: Option B
Explanation

\(y = px^{2} + q ... (i)\)

\(y = 2x^{2} - 1 ... (ii)\)

At x = 2, 

(i): \(y = p(2^{2}) + q = 4p + q\)

(ii): \(y = 2(2^{2}) - 1 = 7\)

\(\therefore \text{The coordinates of the point of intersection = (2, 7)}\)

(i): \(7 = 4p + q \implies p = \frac{7 - q}{4}\)

There is an explanation video available below.


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Explanation Video

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