If two graphs y = px\(^2\) + q and y = 2x\(^2\) -1 intersect at x = 2, find the value of p in terms q.
a
\(\frac{q-8}{7}\)
b
\(\frac{7-q}{4}\)
c
\(\frac{8-q}{2}\)
d
\(\frac{7+q}{8}\)
Explanation
Correct Option
bVideo Explanation
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Discussions (16)
est12her
5 months ago
it is very easy
you will bring out the two equation that is
y=px raise to the power of two +q...(i)
y=2x raise to the power of two -1...(ii)
when x=2(the intersect)
y=2(2) raise to the power of two +q=
y=4p +q...(iii)
do the same thing for equation (ii)
y=7
when y is 7
replace it in equation iii
y=4p+q i.e
7=4p+q
they say fine the value of p in terms of q
i.e find the subject value of p i.e p=7-q divided by 4
that is the final answer
marvey1
9 months ago
i neither don't understand too please can someone help to teach this particular question?..
