\(\frac{a^{3x} - 26a^{2x} + 156a^{x} - 216}{a^{2x} - 24a^{x} + 108}\)
Let \(a^{x} = z\)
\(\therefore = \frac{z^{3} - 26z^{2} + 156z - 216}{z^{2} - 24y + 108} ... (i)\)
Dividing (i) above, we get \(z - 2\)
= \(a^{x} - 2\)
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