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Given that \(p = 1 + \sqrt{2}\) and \(q = 1 - \sqrt{2}\), evaluate \(\frac{p^{2}...

Mathematics
JAMB 2001

Given that \(p = 1 + \sqrt{2}\) and \(q = 1 - \sqrt{2}\), evaluate \(\frac{p^{2} - q^{2}}{2pq}\).

  • A. 2(2+√2)
  • B. -2(2+√2)
  • C. 2√2
  • D. -2√2
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Correct Answer: Option D
Explanation

\(\frac{p^{2} - q^{2}}{2pq} = \frac{(p + q)(p - q)}{2pq}\)

= \(\frac{(1 + \sqrt{2} - (1 - \sqrt{2}))(1 + \sqrt{2} + 1 - \sqrt{2})}{2(1 + \sqrt{2})(1 - \sqrt{2})}\)

= \(\frac{(2\sqrt{2})(2)}{-2}\)

= \(-2\sqrt{2}\)

There is an explanation video available below.


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Explanation Video

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JAMB CBT Software 2025 - Free Download
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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
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