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A.
64 square units
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B.
128/3 square units
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C.
64/3 square units
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D.
32 square units
Correct Answer: Option C
Explanation
\(\int_0 ^4 x^2 dx = \left[\frac{1}{3}x^2+C\right]_0 ^4\\
=\frac{1}{3}\times 4^3 - \frac{1}{3}\times 0^3\\
=\frac{64}{3}-0\\
=\frac{64}{3}\)sq units
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