If the standard deviation of the set of numbers 3, 6, x, 7, 5 is 2, find the least possible value of x.
2
3
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6
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the answer is totally wrong. solution: since in euclidean geometry that state that tanget square is equal to length of nearness scalar multiply by d total length. therefore tz^2=pt×qp= 6^2=x(x+9),
36=x^2+9x collect like term = x^2+9x-36=0
x^2+12x-3x-36
x(x+12)-3(x+12)=0
there fore x is 3 since x cannot be negative
the answer is totally wrong. solution: since in euclidean geometry that state that tanget square is equal to length of nearness scalar multiply by d total length. therefore tz^2=pt×qt= 6^2=x(x+9),
36=x^2+9x collect like term = x^2+9x-36=0
x^2+12x-3x-36
x(x+12)-3(x+12)=0
there fore x is 3 since x cannot be negative
The right answer is actually 3 by the tangent-secant theorem as has already been mentioned.
