Three boys play a game of luck in which their respective chances of winning are \(\frac{1}{2}\), \(\frac{1}{3}\), and \(\frac{1}{4}\). What is the probability that one and only one of the boys wins the game?
a
\(\frac{1}{24}\)
b
\(\frac{1}{12}\)
c
\(\frac{11}{24}\)
d
\(\frac{23}{24}\)
Explanation
Correct Option
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