Find the length XZ in the triangle above.
XY = z,
XZ = y,
YZ = x
y\(^2\) = z\(^2\) + x\(^2\) - 2xz cos 120 y\(^2\) = 2\(^2\) + 1\(^2\) - 2 [2 * 1] cos 120 = 4 + 1 -2 x 2 -cos(180 - 120) = 4 + 1 - 4 [-cos 60] = 5 - 4 [-1/2] = 5 + 2 y\(^2\)= 7 y = √7 m
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