Find ∫(sin x + 2)dx
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx = -cos χ + 2χ + K
There is an explanation video available below.
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}