Explanation

Maximum height, h, v = 0m/s at max height

Recall v\(^2\) = u\(^2\) − 2gh

0\(^2\)  = 80\(^2\) − 2(10)h

0 = 6400 - 20h

h = \(\frac{6400}{20}\)

h = 320 m

b. Time taken to reach maximum height, t

 V = u − gt

0 = 80−10t

10t = 80

t = \(\frac{80}{10}\) = 8s

Since it takes 8 s to reach maximum height, it will also take 8 s to return to the point of projection; hence, it is 16 s

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