7a. A body of mass 5 kg resting on a smooth horizontal plane is acted upon by forces 6i + 2j, 5i + 4j, and 4i − j. Calculate: the velocity of the body
b. the magnitude of its velocity, after 4 seconds
a. Mass , m = 5 kg
Resultant force, f = (6i+2j) + (5i+4j) + (4i−j) = (6+5+4)i + (2+4−1)j = F = 15i + 5j
From Newton second law of motion F = \(\frac{m \Delta V}{\text{t}}\)
F = \(\frac{m(v - u)}{\text{t}}\)
where u=0 ms\(^{−1}\)
F = \(\frac{\text{mv}}{\text{t}}\)
v = \(\frac{\text{Ft}}{\text{m}}\)
v = \(\frac{t(15i + 5j)}{5}\)
v = t(3i + j)m/s
b. Velocity, V after 4 s
v = t(3i + j) = (4)(3i + j) = 12i + 4jm/s.
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