A lift moving with a uniform acceleration of 5 ms\(^{-2}\) carries a body of mass p kg. If the reaction on the floor is 480N, find the value of p [take g =10ms\(^{-1}\)]
Given: a = 5 ms\(^{-2}\), R = 480N, g = 10 ms\(^{-2}\), m = p kg
R - mg = ma
R = mg + ma
R = m(g + a)
480 = p(10 + 5) = p(15)
p = \(\frac{480}{15}\) = 32kg
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}