If a = \(\left| \begin{array}{cc} 3 \\ 2 \end{array} \right|\) and b = \(\left| \begin{array}{cc} -3 \\ 5\end{array} \right|\). Find the vector c such that 4a + 3c = b
4a + 3c = b
4a = 4 \(\left| \begin{array}{cc} 3 \\ 2 \end{array} \right|\) = \(\left| \begin{array}{cc} 12 \\ 8 \end{array} \right|\)
b = \(\left| \begin{array}{cc} -3 \\ 5\end{array} \right|\)
3c = \(\left| \begin{array}{cc} -3 \\ 5\end{array} \right|\) - \(\left| \begin{array}{cc} 12 \\ 8 \end{array} \right|\) = \(\left| \begin{array}{cc} -15 \\ -3\end{array} \right|\)
3c = \(\left| \begin{array}{cc} -15 \\ -3\end{array} \right|\)
c = \(\frac{1}{3}\) \(\left| \begin{array}{cc} -15 \\ -3\end{array} \right|\) = \(\left| \begin{array}{cc} -5 \\ -1\end{array} \right|\)
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