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The mean and median of integers x,y, z, and t are 5 and z, respectively....

Further Mathematics
WAEC 2025

The mean and median of integers x,y, z, and t are 5 and z, respectively. If x< y< z< t and y = 4. Find (x + t)

  • A. 11
  • B. 10
  • C. 12
  • D. 8
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Correct Answer: Option C
Explanation

\(\overline{x}\) = \(\frac{\sum x}{\text{n}}\)

\(\overline{x}\) = \(\frac{ x + y + z + t }{\text{4}}\) = 5

x + y + z + t = 20

but y = 4

x + 4 + z + t = 20

x + z + t = 20 - 4 = 16

median = \(\frac{ y + z}{2}\) = z

= 2z = 4 + z

= 2 z - z = 4

z = 4

Then, x + t + 4 = 16(since z = 4)

x + t = 16 - 4 = 12.


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