Correct Answer: Option C

Explanation

The diagonals bisect each other; hence, the point of intersection is a midpoint M(x, y)

Considering diagonal \(\overline{PR}\), P(-2, 3) and R(2, 6)

The midpoint of a line M(x, y) is given as x = \(\frac{x_1 + x_2}{2}\), y = \(\frac{y_1 + y_2}{2}\)

x = \(\frac{x_1 + x_2}{2}\) = \(\frac{-2 + 2}{2}\) = \(\frac{0}{2}\) = 0

y = \(\frac{y_1 + y_2}{2}\) = y = \(\frac{3 + 6}{2}\) = \(\frac{9}{2}\) = 4\(\frac{1}{2}\)

The coordinate of intersection M = (0, 4\(\frac{1}{2}\))

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