Given that \(\left|
\begin{array}{cc}
2 & -3 \\
1 & 4
\end{array}
\right|
\left|
\begin{array}{c}
6 \\
p
\end{array}
\right|
=
\left|
\begin{array}{c}
3 \\
-26
\end{array}
\right|\) Find p
\(\left|
\begin{array}{cc}
2 & -3 \\
1 & 4
\end{array}
\right|
\left|
\begin{array}{c}
-6 \\
p
\end{array}
\right|
=
\left|
\begin{array}{c}
3 \\
-26
\end{array}
\right|\)
= \(\left|
\begin{array}{cc}
2 \times -6 & -3 \times p \\
1\times -6 & 4 \times p
\end{array}
\right|\) = \(\left|
\begin{array}{c}
3 \\
-26
\end{array}
\right|\)
-12 - 3p = 3
-6 + 4p = -26
-3p = 3 + 12 = 15
p = \(\frac{15}{-3}\) = -5
Therefore, p = - 5
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