In a firing contest, the probabilities that Kojo and Kwame hit the target are \(\frac{2}{5}\) and \(\frac{1}{3}\) respectively. What is the probability that none of them will hit the target?
Probability that Konjo hit the target Pr(K) = \(\frac{2}{5}\)
Prob that Kwame hit the target Pr(kw) = \(\frac{1}{3}\)
Prob hat kojo doesn't hit the target Pr(K') = 1 - \(\frac{2}{5}\) = \(\frac{3}{5}\)
Prob that kwame doesn't hit the target pr(kw') = 1 - \(\frac{1}{3}\) = \(\frac{2}{3}\)
Prob that none hit the target = kojo and kwame doesn't hit the target = \(\frac{3}{5} \times \frac{2}{3}\) = \(\frac{2}{5}\)
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