Correct Answer: Option A

Explanation

Sum of the series 96 + 24 + 6 + ....

Common ratio, r = \(\frac{24}{96}\) = \(\frac{1}{4}\)

First term, a = 96

Sum to infinity , S\(_∞\) = \(\frac{\text{a}}{1 - r}\)  = \(\frac{96}{(1 - \frac{1}{4})}\)

S\(_∞\) = \(\frac{96}{\frac{3}{4}}\) = 96 x \(\frac{4}{3}\) = 32 x 4 = 128.

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