Given that (\(\sqrt{3}\) - 5\(\sqrt{2}\))(\(\sqrt{3}\) + \(\sqrt{2}\)) = p + q\(\sqrt{6}\). Find q
\((\sqrt{3} - 5\sqrt{2})(\sqrt{3} + \sqrt{2}) = p + q\sqrt{6}\)
Expanding the left-hand side:
\(\sqrt{3}(\sqrt{3} + \sqrt{2}) - 5\sqrt{2}(\sqrt{3} + \sqrt{2})\)
Simplifying: \(\sqrt{9} + \sqrt{6} - 5\sqrt{6} - 5\sqrt{4}\)
\(3 - 4\sqrt{6} - 10\)
\(-7 - 4\sqrt{6}\)
Comparing with the right-hand side:
\(-7 - 4\sqrt{6} = p + q\sqrt{6}\)
From this, we have:
\(-4\sqrt{6} = q\sqrt{6}\)
This leads to: q = -4
And similarly: -7 = p \(\quad \Rightarrow \quad\) p = -7
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