Solve the inequality 2x\(^2\) + 5x - 3 ≥ 0.
2x\(^2\) + 5x - 3 ≥ 0
2x\(^2\) + 6x - x - 3 \(\geq\) 0
2x(x + 3) - 1(x + 3) \(\geq\) 0
(2x - 1)(x + 3) \(\geq\) 0
2x \(\geq\) 1 or x \(\geq\) -3
x \(\geq\) \(\frac{1}{2}\)
\(\therefore\) x ≤ -3 or x ≥ \(\frac{1}{2}\) the only valid answer
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