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2024 WAEC Further Mathematics Theory Two events M and N are such that P(M) = \(\frac{1}{2}\), P(N) =  \(\frac{9}{20}\) and...

Further Mathematics
WAEC 2024

Two events M and N are such that P(M) = \(\frac{1}{2}\), P(N) =  \(\frac{9}{20}\) and P(M  N) = \(\frac{11}{50}\)

(a) P(M ∩ N'):  (b) P(M' ∩ N)

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Explanation

Given that: P(M) = \(\frac{1}{2}\), P(N) =  \(\frac{9}{20}\) and P(M  N) = \(\frac{11}{50}\)

Using the diagram above

(a) P(M ∩ N') = \(\frac{1}{2} - \frac{11}{50}\) = \(\frac{25 - 11}{50}\) = \(\frac{14}{50}\) = \(\frac{7}{25}\)

(b) P(M' ∩ N) =  \(\frac{9}{20} - \frac{11}{50}\) =  \(\frac{45 - 22}{100}\) = \(\frac{23}{100}\).


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