The scores of some students in a class test are 4, 6, 1, 8, 9, 5, and 2. Calculate, correct to one decimal place, the mean deviation of their scores.
The scores of some students in a class test are 4, 6, 1, 8, 9, 5, and 2
M.D = \(\frac{\sum {|x - \overline{x}|}}{n}\)
\(\overline{x}\) = \(\frac{4 + 6 + 1 + 8 + 9 + 5 + 2}{7}\) = \(\frac{35}{7}\) = 5
| x | x - \(\overline{x}\) |
|x - \(\overline{x}\)| |
| 4 | 4 - 5 = - 1 | 1 |
| 6 | 6 - 5 = 1 | 1 |
| 1 | 1 - 5 = - 4 | 4 |
| 8 | 8 - 5 = 3 | 3 |
| 9 | 9 - 5 = 4 | 4 |
| 5 | 5 - 5 = 0 | 0 |
| 2 | 2 - 5 = - 3 | 3 |
\(\sum {|x - \overline{x}|}\) = 16
M.D = \(\frac{\sum {|x - \overline{x}|}}{n}\) = \(\frac{16}{7}\) = 2.2857 ≈ 2.3
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