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The point P(-3, 5) lies on a line which is perpendicular to 2x - 4y...

Further Mathematics
WAEC 2024

The point P(-3, 5) lies on a line which is perpendicular to 2x - 4y + 3 = 0. Find the equation of the line.

  • A. y - 2x - 11 = 0
  • B. y - 2x - 1 = 0
  • C. y + 2x + 1 = 0
  • D. y + 2x + 11 = 0
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Correct Answer: Option C
Explanation

P(-3, 5), The given line, 2x - 4y + 3 = 0

2x - 4y + 3 = 0 rearrange to the slope-intercept form

4y = 2x + 3, divide through by 4

y = \(\frac{1}{2}\) x + \(\frac{3}{4}\)

M\(_1\) = \(\frac{1}{2}\), then M\(_2\) = -2 (condition for perpendicularity)

y - y\(_1\) = M\(_2\)(x - x\(_1\))

y - 5 = -2(x - (-3))

y - 5 = -2x - 6

y - 5 + 6 + 2x = 0

y + 2x + 1 = 0 becomes the equation of the line.


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