Correct Answer: Option B

Explanation

f(x) = \(\frac{2 - x}{x}\), x ≠ 0

let the inverse of f \(\frac{2 - 1}{x}\), be y

y = \(\frac{2 - x}{x}\), 

xy = 2 - x 

xy + x = 2

x(y + 1) = 2

x = \(\frac{2}{y + 1}\) ⇒ \(\frac{2}{x +1}\)

Thus, the inverse of f(x) = \(\frac{2 - x}{x}\), x ≠ 0 =  \(\frac{2}{x +1}\) provided x ≠ -1

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