Correct Answer: Option C

Explanation

log\(_2^x\) = 2, in index form = x = 2\(^2\) = 4

So, log\(_x^{128}\) = log\(_4^{128}\) = log\(_{2^2}^{2^7}\) = \(\frac{7}{2}\)log\(_2^2\) = \(\frac{7}{2}\)

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