Correct Answer: Option C

Explanation

n\(^{th}\) = (5n - 2)

1st term = 5 - 2 = 3

2nd term = 10 - 2 = 8

3rd term = 15 - 2 = 13

Hence, common difference, d = 5

S\(_n\) = \(\frac{n}{2}\)[2a + (n - 1)d]

S\(_{12}\) = \(\frac{12}{2}\)[2 x 3 + (12 - 1)5]

= 6[6 + 11 x 5] = 6[6 + 55] = 6 x 61 = 366.

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