Correct Answer: Option C

Explanation

\(P : (x, y) → (2x + y, -2y)\)

\(p\begin{bmatrix} x\\y\end{bmatrix}=\begin{bmatrix} 2x & y\\0 &-2y\end{bmatrix}\)

\(\therefore p = \begin{bmatrix} 2 & 1\\0 &-2\end{bmatrix}\)

\(\therefore p^2 = \begin{bmatrix} 2&1\\0&-2\end{bmatrix}\) \(\begin{bmatrix} 2&1\\0&-2\end{bmatrix}\) = \(\begin{bmatrix} 4&0\\0&4\end{bmatrix}\)

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