In how many ways can a committee of 3 women and 2 men be chosen from a group of 7 men and 5 women?
For choosing, its different 'combinations'
Options - 7 men, 5 women
To pick - 2 men, 3 women
∴ The number of ways to choose a committee of 3 women and 2 men from a group of 7 men and 5 women is:
=\(^5C_3 \times ^7C_2\)
=\(\frac{5\times4\times3}{3\times2}\times\frac{7\times6}{2\times1}\)
=\(10\times21\)
=210
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}