The probability that Abiola will be late to the office on a given day is 2/5. In a given working week of six days, find, correct to four significant figures, the probability that he will:
(a) only be late for 3 days.
(b) not be late in the week:
(c) be late throughout the six days.
he will be late to office = 2/5
he will not be late to office is = 1 - 2/5 = 3/5
If he will be late for 3 days only, he will also not be late for 3 days
\(\frac{2}{5}\) * \(\frac{2}{5}\) * \(\frac{2}{5}\) * \(\frac{3}{5}\) * \(\frac{3}{5}\) * \(\frac{3}{5}\)
p = 0.0138
(b) not be late to office is = 1 - 2/5 = 3/5
\(\frac{3}{5}\) * \(\frac{3}{5}\) * \(\frac{3}{5}\) * \(\frac{3}{5}\) * \(\frac{3}{5}\) * \(\frac{3}{5}\)
p = 0.0467
(c) be late to office = 2/5
\(\frac{2}{5}\) * \(\frac{2}{5}\) * \(\frac{2}{5}\) * \(\frac{2}{5}\) * \(\frac{2}{5}\) * \(\frac{2}{5}\)
p = 0.0041
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