Correct Answer: Option A

Explanation

2x\(^2\) + 7x - 15 ≥ 0

2x\(^2\) -3x + 10x - 15 ≥ 0
x(2x - 3) + 5(2x - 3) ≥ 0
(x+5)(2x-3) ≥ 0
the points on x-axis where the graph ≥ 0

x ≤ -5 or x ≥ \(\frac{3}{2}\)

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