Correct Answer: Option C

Explanation

\(4p_2 + 4C_2 - 4p_3\)

\(np_r = \frac{n!}{[n-r]!} and  nC_r = \frac{n!}{[n-r]!r!} \)

= \(\frac{4!}{[4-2]!} + \frac{4!}{[4-2]!2!} - \frac{4!}{[4-3]!} = \frac{4!}{2!} + \frac{4!}{2!2!} - \frac{4!}{1!}\)

= \(\frac{4*3*2!}{2!} + \frac{4*3*2!}{2!2!} - \frac{4*3*2*1}{1!}\)

12 + 6 - 24 = -6

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