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If \(\frac{15 - 2x}{(x+4)(x-3)}\) = \(\frac{R}{(x+4)}\) \(\frac{9}{7(x-3)}\), find the value of R

Further Mathematics
WAEC 2021

If \(\frac{15 - 2x}{(x+4)(x-3)}\) = \(\frac{R}{(x+4)}\) \(\frac{9}{7(x-3)}\), find the value of R

  • A. \(\frac{-32}{7}\)
  • B. \(\frac{-23}{7}\)
  • C. \(\frac{23}{7}\)
  • D. \(\frac{32}{7}\)
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Correct Answer: Option C
Explanation

\(\frac{15 - 2x}{(x+4)(x-3)}\) = \(\frac{R}{(x+4)}\) + \(\frac{9}{7(x-3)}\)

 15-2x = R(x - 3) +9(x +4)/7

Put x =-4, we have 15 -2(-4) = -7R

23 -7R;

R = 23/7


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NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789
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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
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