If \(\frac{15 - 2x}{(x+4)(x-3)}\) = \(\frac{R}{(x+4)}\) + \(\frac{9}{(x-3)}\), find the value of R
\(\frac{15 - 2x}{(x+4)(x-3)}\) = \(\frac{R}{(x+4)}\) + \(\frac{9}{(x-3)}\)
15 - 2x = R(x - 3) + 9(x +4)
Put x = -4, we have 15 -2(-4) = -7R
23 = -7R;
R = \(\frac{-23}{7}\)
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