2x\(^3\) - 4x + 2y\(^2\) - 6y - 2 = 0
Divide through by 2: x\(^2\) - 2x + y\(^2\) -3y -1 = 0
x\(^2\) -2x + y\(^2\) - 3y = 1
x\(^2\) -2x + 1 + y\(^2\) - 3y + \(\frac{9}{4}\)
= 1+ 1 + \(\frac{9}{4}\)
= (x- 1)\(^2\) (y - 3/2)\(^2\)
= \(\sqrt{\frac{17}{4}}\)
r = \(\frac{\sqrt{17}}{2}\)
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}