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If √5 cosx + √15sinx = 0, for 0° < x < 360°, find the...

Further Mathematics
WAEC 2021

If √5 cosx + √15sinx = 0, for 0° < x < 360°, find the values of x.

  • A. 30° and 150°
  • B. 150° and 210°
  • C. 150° and 330°
  • D. 210° and 330°
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Correct Answer: Option C
Explanation

√5 cosx + √15sinx = 0;

√5 (cosx + √3sinx) = 0

cosx = -sinx√3;  \(\frac{sinx}{cos}\) = \(\frac{-1}{√3}\)

tanx =  \(\frac{-1}{√3}\);  x = 150° or 330°


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