If 2y\(^2\) + 7 = 3y - xy, find \(\frac{dy}{dx}\)
2y\(^2\) + 7 = 3y - xy, find \(\frac{dy}{dx}\)
4y\(\frac{dy}{dx}\) + 0 = 3 \(\frac{dy}{dx}\) - (x\(\frac{dy}{dx}\) + y)
{4y+ x - 3}\(\frac{dy}{dx}\) = - y
= \(\frac{-y}{4y + x - 3}\)
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