Solve (\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)
(\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)
3\(^{-2(x + 2)}\) = 3\(^{5(x - 2)}\);
-2(x+2) = 5(x - 2)
-2x -4 = 5x - 10
-7x = -6
x = \(\frac{6}{7}\)
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