Find the angle between i + 5j and 5i - J
a = i + 5j and b = 5i - j
cos\(\theta\) = \(\frac{a.b}{|a|.|b|}\)
= \(\frac{(1 \times 5) + (5x - 1)}{(\sqrt{1^2 + 5^2}) (5^2 + (-1))^2}\)
= \(\frac{5 - 5}{\sqrt{26}\times \sqrt{26}}\) = 0
x = cos\(^{-1}\)(0), x = 90\(^o\)
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}