Correct Answer: Option D

Explanation

\(\frac{1}{x^2 - 4} = \frac{P}{(x + 2)} + \frac{Q}{(x - 2)}\)

I = p(x - 2) + Q(x + 2)

Let x = 2

I = P(2 - 2) + Q(2+ 2)

I = -4Q 

Q = \(\frac{1}{4}\) 

Let x = -2

I = P(-2  - 2) + Q(-2 + 2)

I = -4p 

P = \(\frac{1}{-4}\) 

PQQ = - \(\frac{1}{4} + \frac{1}{4}\)

= 0

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