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Evaluate tan 75\(^o\); leaving the answer in surd form (radicals) 

Further Mathematics
WAEC 2019

Evaluate tan 75\(^o\); leaving the answer in surd form (radicals) 

  • A. \(\sqrt{3 + 2}\)
  • B. \(\sqrt{3 + 1}\)
  • C. \(\sqrt{3 - 1}\)
  • D. \(\sqrt{3 - 2}\)
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Correct Answer: Option D
Explanation

Tan 75\(^o\) = Tan (45\(^o\) + 30\(^o\))

= \(\frac{\tan 45^o + \tan 30^o}{1 - \tan 45^o \tan 30^o}\)

= \(\frac{\sqrt{3} + 1}{\sqrt{3}  - 1}\)

RATIONALIZE THE DENOMINATOR

= \(\frac{\sqrt{3} + 1}{\sqrt{3}  - 1}\) X \(\frac{\sqrt{3} + 1}{\sqrt{3}  +1}\)

= \(\frac{4 + 2\sqrt{3}}{3  - 1}\)

= \(\frac{2(2 + \sqrt{3})}{2}\)

= 2 + \(\sqrt{3}\)


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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995