A uniform beam, WX, of length 90 cm and weight 50N is suspended on a pivot, 35 cm from W. It is kept in equilibrum by a means of forces T and 20N applied at Y and Z respectively. |WY| = 10cm and |XZ| = 10cm. Find the value of T
The weight 50N acts at G, the centre of the beam. Given that the system is in equilibrium, therefore taking moments about the pivot, we have 25 x T = 50 x 10 x 45 and when simplified and solved for T
T = \(\frac{1500}{25}\) = 56N
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