Explanation

If we let \(\beta\)  be the angle between the forces 10N and 16N,

then \(\beta\) = (180\(^o\) - \(\theta\))

Applying the cosine rule; cos\(\theta\) = \(\frac{10^2 + 16^2 - 14^2}{2 \times 10 \times 16}\) = 0.5

If \(\theta\) = cos\(^{-1}\)(0.5) = 60\(^o\) 

\(\beta\) = 180\(^o\) - 60\(^o\) = 120\(^o\) 

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