Explanation

\(f(x) = 6x^{3} + 13x^{2} + 2x - 5\)

f(-1) = 0 implies (x + 1) is a factor.

Using the method of long division, you find the other factors.

\(\frac{6x^{3} + 13x^{2} + 2x - 5}{x + 1} = 6x^{2} + 7x - 5\) (check).

\(6x^{2} + 7x - 5 = 6x^{2} - 3x + 10x - 5\)

\(3x(2x - 1) + 5(2x - 1)\)

Hence, the factors of f(x) are (x + 1), (3x + 5) and (2x - 1).

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