A car moving with an initial velocity, u, travels in a straight line with a constant acceleration of 3ms\(^{-2}\) until it attains a velocity of 33ms\(^{-1}\) after 6 seconds. Calculate the distance travelled by the car.
We find the initial velocity using the formula \(v = u + at\)
\(33 = u + 3(6) \implies 33 = u + 18\)
\(u = 15ms^{-1}\)
Distance \(s = ut + \frac{1}{2} at^{2}\)
= \(15 \times 6 + \frac{1}{2} (3)(6^{2})\)
= \(90 + 54 = 144m\)
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